# At 450 K, Kp= 2.0 × 1010/bar for the given reaction at equilibrium. What is Kc at this temperature?

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At 450 K, Kp= 2.0 × 1010/bar for the given reaction at equilibrium.

What is Kc at this temperature?

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For the given reaction,

∆n = 2 – 3 = – 1

T = 450 K

R = 0.0831 bar L bar K–1 mol–1

Kp = 2.0 × 1010 bar –1

We know that,