LIVE Course for free

Rated by 1 million+ students
Get app now
+1 vote
by (29.8k points)

At 450 K, Kp= 2.0 × 1010/bar for the given reaction at equilibrium. 

What is Kc at this temperature?

1 Answer

+1 vote
by (128k points)
selected by
Best answer

For the given reaction, 

∆n = 2 – 3 = – 1 

T = 450 K 

R = 0.0831 bar L bar K–1 mol–1 

Kp = 2.0 × 1010 bar –1 

We know that,


Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.