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Solve the following equations:

i 4(x + 12) = 8 

ii. 3y + 4 = 5y – 6

1 Answer

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Best answer

i. 4(x + 12) = 8 

∴4x + 48 = 8 

∴4x + 48 – 48 = 8 – 48 ….(Subtracting 48 from both sides) 

∴ 4x = -40 

∴ x = -40/4

∴ x = -10 

ii. 3y + 4 = 5y – 6 

∴ 3y + 4 + 6 = 5y – 6 + 6 ….(Adding 6 on both sides) 

∴ 3y + 10 = 5y 

∴ 3y + 10 – 3y = 5y – 3y ….(Subtracting 3y from both sides) 

∴ 10 = 2y 

∴ 2y = 10 

∴ y = 10/2

∴ y = 5

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