# From the given figure, find the length of hypotenuse AC and the perimeter of ∆ABC.

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From the given figure, find the length of hypotenuse AC and the perimeter of ∆ABC.

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In ∆ABC, ∠B = 90° , and l(BC) = 21, and l(AB) = 20

∴ According to Pythagoras’ theorem,

∴ l(AC)= l(BC)+ l(AB)

∴ l(AC)= 21+ 20

∴ l(AC)= 441 + 400

∴ l(AC)= 841

∴ l(AC)= 29

∴ l(AC) = 29

Perimeter of ∆ABC = l(AB) + l(BC) + l(AC)

= 20 + 21 + 29

= 70

∴ The length of hypotenuse AC is 29 units, and the perimeter of ∆ABC is 70 units.