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0 votes
8.5k views
in Electrostatics by (48.7k points)
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Two plates are 2 cm apart. If a potential difference of 10 V is applied between them. The electric field between the plates will be

(a) 20 NC-1 

(b) 500 NC-1 

(c) 5 NC-1 

(d) 250 NC-1

2 Answers

+1 vote
by (120 points)
selected by
 
Best answer

Answer : 500 NC-1

Given : x = 2 cm 

             V = 10V 

             E = ? 

Solution : We know that ,

E = V/x 

= 10/2 × 10-2

= 5 × 102

= 500 NC-1

\(\therefore\) The electric field will be 500 NC-1

0 votes
by (41.9k points)
edited by

(b) 500 NC-1 

\(\frac {V}{d}\)\(\frac{10}{2 \times 10^{-2}}\) = 500 NC-1

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