Fewpal
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Calculate 

(a) ∆G° and 

(b) the equilibrium constant for the formation of NO2 from NO and O2 at 298 K 

Where: 

fG° (NO2) = 52.0 kJ/mol 

fG° (NO) = 87.0 kJ/mol 

fG° (O2) = 0 kJ/mol 

1 Answer

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(a) For the given reaction, 

∆G° = ∆G°( Products) – ∆G°( Reactants)

 ∆G° = 52.0 – {87.0 + 0} 

= – 35.0 kJ mol–1 

(b) We know that, 

∆G° = RT log Kc 

∆G° = 2.303 RT log Kc 

Hence, the equilibrium constant for the given reaction Kc is 1.36 × 106 

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