Let the given lines be l1 and l2 which have two bisectors of angle as B1 and B2. Any point on the bisector is equidistant from the two lines
Thus we will have four points like P1,P2,P3 and P4
Let P(x,y) which is equidistant
Solving (1) with (3) and (4), and then (2) with (3) and (4) we get the points (−7,−5/4),(−27/2,−49/8),(1/2,15/8),(−6,−3)