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in Linear Equations by (47.3k points)
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Draw the graph of the linear equation 2x + 3y = 12. At what points, the graph of the equation cuts the x-axis and the y-axis?

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by (49.8k points)
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The given equation is 2x + 3y = 12. To draw the graph of this equation, we need at least two points lying on the graph. 

From the equation, we have y = (12 - 2x)/3

For x = 0, y = 4, therefore, (0, 4) lies on the graph.

For y = 0, x = 6, therefore, (6, 0) lies on the graph.

Now plot the points A (0, 4) and B (6, 0) and join them (see Fig), to get the line AB. Line AB is the required graph. 

You can see that the graph (line AB) cuts the x-axis at the point (6, 0) and the y-axis at the point (0, 4).

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