Given here: Atomic mass of iron = 56
now, 1 mole of iron contains 56 g of iron.
no. of moles in 224 g iron = n= 224/56 = 4
Now,
Total number of electrons or protons in 4 moles of iron = n × avagadro number = 4 × 6.032 × 1023
0.01 % of 4 × 6.032 × 1023 = a = (0.01/100) × 4 × 6.032 × 1023 = 2.41×1020
Now, defecient negative charge = a × charge on electron
= 2.41×1020 × 1.602 × 10-19 = 38.6 C
Positive charge acquired by 224g iron = defecient negative charge = 38.6 C