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in Physics by (349 points)
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Calculate the charges of an iron particle of mass 224 mg if 0.01% of the electrons are removed from it.

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Given here: Atomic mass of iron = 56
now, 1 mole of iron contains 56 g of iron.
no. of moles in 224 g iron = n= 224/56 = 4
Now,
Total number of electrons or protons in 4 moles of iron = n ×​ avagadro number = 4 ×​ 6.032 ×​ 1023 
0.01 % of  4 ×​ 6.032 ×​ 1023 ​ =  a = (0.01/100) × 4 ×​ 6.032 ×​ 1023 ​= 2.41×1020

Now, defecient negative charge = a ×​ charge on  electron  

= 2.41×​1020  × 1.602 × 10-19 = 38.6 C

Positive charge acquired by 224g iron = defecient negative charge​  = 38.6 C​

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