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+1 vote
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in Integral Calculus I by (48.4k points)
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Integrate ∫(e2x - 1)/(e2x + x) dx

1 Answer

+1 vote
by (48.0k points)
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Best answer

Dividing numerator and denominator by ex, we get

∫(e- e-x)/(e+ e-x)dx

Now d/dx(ex + e-x

= ex - e-x 

= log(ex + e-x) +c

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