Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.6k views
in p-Block Elements – I by (34.6k points)
closed by

Sodium borohydride reacts with iodine in the presence of diglyme to give A. A heated at 388 K give B. A heated at 373 K in sealed tube to form C. A further heated at red hot condition to give element D. Find out A, B, C and D. Give the reactions.

1 Answer

+1 vote
by (47.6k points)
selected by
 
Best answer

1. Sodium borohydride reacts with iodine in the presence of diglyme to give diborane (A).

2. Diborane (A) heated at 388 K gives pentaborane (11) (B).

3. Diborane (A) heated at 373 K in the sealed tube to form decaborane (14) (C).Diborane (A) heated at red hot conditions to give element boron (D) Diborane B2H6

A Diborane  B2H6
B Pentaborane-11 B5H11
C Decaborane-14 B10H14
D Boron B

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...