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in Integral Calculus II by (48.4k points)
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The marginal revenue (in thousands of Rupees) functions for a particular commodity is 5 + 3e-0.03x where x denotes the number of units sold. Determine the total revenue from the sale of 100 units. (Given e = 0.05 approximately)

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by (48.0k points)
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Given, marginal Revenue R'(x) = 5 + 3e-0.03x 

Total revenue from the sale of 100 units is 

R = 500 - 100 e-3 + 100

R = 600 - 100(0.05) = 595

Total revenue = 595 x 1000 = Rs. 5,95,000

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