Sarthaks Test
+1 vote
2.2k views
in Chemistry by (29.7k points)
reshown by

The ionization constant of acetic acid is 1.74 × 10–5 . Calculate the degree of dissociation of acetic acid in its 0.05 M solution. Calculate the concentration of acetate ion in the solution and its pH. 

Please log in or register to answer this question.

1 Answer

+1 vote
by (128k points)

since Ka  >> Kw; 

Method 2 

Degree of dissociation, 

c = 0.05 M Ka = 1.74 × 10–5

Thus, concentration of CH3COO– = c.α 

Hence, the concentration of acetate ion in the solution is 0.00093 M and its Ph is 3.03. 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...