Fewpal
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Calculate the pH of the following solutions: 

(a) 2g of TlOH dissolved in water to give 2 litre of solution.

(b) 0.3g of Ca(OH)2 dissolved in water to give 500 mL of solution. 

(c) 0.3g of NaOH dissolved in water to give 200 mL of solution. 

(d) 1mL of 13.6 M HCl is diluted with water to give 1 litre of solution.

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(a) For 2g of TlOH dissolved in water to give 2 L of solution: 

(b) For 0.3 g of Ca(OH)2 dissolved in water to give 500 mL of solution: 

(c) For 0.3 g of NaOH dissolved in water to give 200 mL of solution: 

(d) For 1mL of 13.6 M HCl diluted with water to give 1 L of solution: 

13.6 × 1 mL = M2 × 1000 mL 

(Before dilution) (After dilution) 

13.6 × 10–3 = M2 × 1L M2 

= 1.36 × 10–2 [H+] = 1.36 × 10–2 pH = – log (1.36 × 10–2

= (– 0.1335 + 2) = 1.866 =1.87 

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