Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
1.6k views
in Magnetism and Magnetic Effects of Electric Current by (48.6k points)
closed by

State and explain the Biot – Savart Law.

1 Answer

+1 vote
by (48.2k points)
selected by
 
Best answer

Biot and Savart experimentally observed that the magnitude of magnetic field d\(\vec B\) at a point P at a distance r from the small elemental length taken on a conductor carrying current varies 

(i) directly as the strength of the current I 

(ii) directly as the magnitude of the length element \(\vec {dl}\)

(iii) directly as the sine of the angle (say,θ) between \(\vec {dl}\) and\(\hat r\).

(iv) inversely as the square of the distance between the point P and length element \(\vec {dl}\).

This is expressed as 

Here vector d\(\vec B\) is perpendicular to both I \(\vec{dl}\) (pointing current carrying conductor the direction of current flow) and the unit vector and \(\hat r\) directed from \(\vec{dl}\)  toward point P The equation 1 is used to compute the magnetic field only due to a small elemental length \(\vec{dl}\) of the conductor. The net magnetic field at P due to the conductor is obtained from principle of superposition by considering the contribution from all current elements I \(\vec{dl}\) . Hence integrating equation (1), we get

where the integral is taken over the entire current distribution.

Case:

1. If the pont P lies on the ckonductor, then θ = 0°. Therefore, d is zero. 

2. If the point lies perpendicular to the conductor, then θ = 90°. Therefore, d\(\vec{B}\) is maximum and is given by d\(\vec{B}\) = \(\frac{Idl}{r^2}\)\(\hat n\).

where \(\hat n\) is the unit vector perpendicular to both l \(\vec{dl}\) and \(\hat r\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...