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in Electromagnetic Induction and Alternating Current by (48.5k points)
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An electron is moving at 106 ms-1 in a direction parallel to a current of 5A flowing through an infinitely long straight wire, separated by a perpendicular distance of 10 cm in air. Calculate the magnitude of the force experienced by the electron.

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Magnetic field of the straight wire carrying a current of 2 A, at a distance of 10cm or 0. lm from it is

This field acts perpendicular to the direction of the electron. So magnetic force on the electron is

F = qv B sin 90° = 1.6 x 10-19 x 106x  10-5 x 1 

F = 1.6 x 10-18 N

Common Errors and Its Rectifications

Common Errors:

1. Students may not know about arrow mark in the figures, (diagram) 

2. Students wrongly mention the unit of magnetic induction. 

Eg. 0.5 x 10-5 Tesla. 

Most of the children makes the mistakes in this area. 

3. Student may confuse the direction of current versus produced magnetic induction.

Rectifications: 

1. Arrow mark is importance to show where the electric and magnetic fields are directed. 

2. The correct unit of magnetic induction of T (or) tesla. 

3. If the current moves in upward the magnetic induction is anti-clock. If the current in downward, the magnetic induction is clockwise.

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