According to the question,
ABCD is a trapezium
∠A = ∠B = 45º
We know that,
Angles opposite to each other in quadrilateral are supplementary.
Then, we have,
∠A + ∠C = 180º
45o + ∠C = 180º
∠C = 180o – 45o
∠C = 135o
Similarly,
We have,
∠B + ∠D = 180º
45o + ∠D = 180º
∠D = 180o – 45o
∠D = 135o