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Calculate the pH of the resultant mixtures: 

(a) 10 mL of 0.2M Ca(OH)2 + 25 mL of 0.1M HCl 

(b) 10 mL of 0.01M H2SO4 + 10 mL of 0.01M Ca(OH)

(c) 10 mL of 0.1M H2SO4 + 10 mL of 0.1M KOH 

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(a)    

Thus, excess of OH = .0015 mol 

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