Question

The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 13 m, 14 m and 15 m. The advertisements yield an earning of Rs 2000 per m² a year. A company hired one of its walls for 6 months. How much rent did it pay?

Answer 1

According to the question,

The sides of the triangle are 13 m, 14 m and 15 m

Let a = 13, b = 14, c = 15

s = (a + b + c)/2

⇒ s = (13 + 14 + 15)/2

= 42/2

= 21.

Area of triangle = √s(s-a)(s-b)(s-c)

= √21(21-13)(21-14)(21-15)

= √21×8×7×6

= 84m²

Cost of advertisements for a year = Area of triangle × Cost per m²

= 84×2000

= Rs. 168000

Since the board is rented for only 6 months:

Cost of advertisements for 6 months = (6/12) × 168000

= Rs. 84000