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+1 vote
2.8k views
in Electromagnetic Induction and Alternating Current by (48.5k points)

The instantaneous value of alternating current and voltage are given as i = \(\frac{1}{\sqrt2}\) sin (100 πt) A and e = \(\frac{1}{\sqrt2}\) sin(100 πt +\(\frac{π}{3}\)) volt. Find the average power in watts consumed in the circuit.

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1 Answer

+1 vote
by (48.1k points)

Common Errors and its Rectifications: 

Common Errors:

1. Students sometimes may confuse the peak current and instantaneous value of current and emf. 

2. They may confuse in the area of R, L and C with AC. The relation between current and induced emf.

Rectifications:

1. Instantaneous current, i = I0 sin tot Peak current, I0 = √2 Irms  Instantaneous emf, e = E0 sin cor Peak emf, E0 = √2 Erms  

2. In Inductor: current is \(\frac{π}{2}\) rad less than that of emf. 

In Resistor: current and emf are same phase. 

In Capacitor: current is \(\frac{π}{2}\) rad greater than that of emf.

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