# Let m be the mid-point and l be the upper class limit of a class in a continuous frequency distribution.

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Let m be the mid-point and l be the upper class limit of a class in a continuous frequency distribution. The lower class limit of the class is:

(A) 2m + l

(B) 2m – l

(C) m – l

(D) m – 2l

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(B) 2m – l

Explanation:

Let x be the lower class limit of a continuous frequency distribution

Let y be the upper class limit of a continuous frequency distribution

Now, according to the question,

Mid-point of a class = (x+y) /2

=m

x+y = 2m or, x+l=2m

It is given that, y = l = upper class limit

x=2m-l

Hence, the lower class limit of the class = 2m-l

Hence, option (B) is the correct answer.