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Can the number 6^n, n being a natural number, end with the digit 5? Give reasons.

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Can the number 6n, n being a natural number, end with the digit 5? Give reasons.

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No, because 6n = (2 × 3)n = 2n × 3n , so the only primes in the factorisation of 6n are 2 and 3, and not 5. 

Hence, it cannot end with the digit 5.

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