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+1 vote
2.6k views
in Applications of Vector Algebra by (49.5k points)
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The vector equation vector r = (i - 2j - k) + t(6j - k) represents a straight line passing through the points …

(a) (0, 6, -1) and (1, -2, -1) 

(b) (0, 6, -1) and (-1, -4, -2) 

(c) (1, -2, -1) and (1, 4, -2) 

(d) (1, -2, -1) and (0, -6, 1)

1 Answer

+2 votes
by (48.8k points)
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Best answer

(c) (1, -2, -1) and (1, 4, -2)

The required vector equation is vector r = vector a + t(vector(b - a))

From (1) and (2) 

The points are (1, -2, -1) and (1, 4, -2)

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