Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
541 views
in Optics by (48.5k points)
closed by

A concave mirror of focal length 15 cm forms an image having twice the linear dimensions of the object. The position of the object, when the image is virtual will be 

(a) 22.5 cm 

(b) 7.5 cm 

(c) 30 cm 

(d) 45 cm

1 Answer

+1 vote
by (48.1k points)
selected by
 
Best answer

(b) 7.5 cm 

For virtual images, m = \(\frac{-v}{u}\) = +2 or v = -2u

As \(\frac{1}{u} + \frac{1}{v} = \frac{1}{f}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...