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0 votes
13.2k views
in Optics by (48.5k points)
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An object of length 2.5 cm is placed at the principal axis of a concave mirror at a distance 1.5f. The image height is

(a) + 5 m 

(b) -5 cm 

(c) – 10 cm 

(d) + 1 cm

1 Answer

+1 vote
by (48.1k points)
selected by
 
Best answer

(b) -5 cm

m = \(\frac{f}{f-u} = \frac{f}{f-1.5f}\) = -2cm

Height image = m x height of object -2 x 2.5 = – 5 cm

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