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in Linear Equations by (47.4k points)
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Graphically, solve the following pair of equations:

2x + y = 6

2x – y + 2 = 0

Find the ratio of the areas of the two triangles formed by the lines representing these equations with the x-axis and the lines with the y-axis.

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Given equations are 2x + y = 6 and 2x – y + 2 = 0

Table for equation 2x + y – 6 = 0, for x = 0, y = 6, for y = 0, x = 3.

Let A1 and A2 represent the areas of triangles ACE and BDE respectively.

Let, Area of triangle formed with x -axis = T1

T1 = Area of △ACE = ½ × AC × PE

T1 = ½ × 4 × 4 = 8

And Area of triangle formed with y – axis = T2

T1 = Area of △BDE = ½ × BD × QE

T1 = ½ × 4 × 1 = 2

T1:T2 = 8:2 = 4:1

Hence, the pair of equations intersect graphically at point E(1,4)

i.e., x = 1 and y = 4.

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