Given equations are 2x + y = 6 and 2x – y + 2 = 0
Table for equation 2x + y – 6 = 0, for x = 0, y = 6, for y = 0, x = 3.
Let A1 and A2 represent the areas of triangles ACE and BDE respectively.
Let, Area of triangle formed with x -axis = T1
T1 = Area of △ACE = ½ × AC × PE
T1 = ½ × 4 × 4 = 8
And Area of triangle formed with y – axis = T2
T1 = Area of △BDE = ½ × BD × QE
T1 = ½ × 4 × 1 = 2
T1:T2 = 8:2 = 4:1
Hence, the pair of equations intersect graphically at point E(1,4)
i.e., x = 1 and y = 4.