Question

Draw the graphs of the equations x = 3, x = 5 and 2x – y – 4 = 0. Also find the area of the quadrilateral formed by the lines and the x–axis.

Answer 1

Given equation of lines x = 3, x = 5 and 2x - y - 4 = 0.

Table for line 2x – y – 4 = 0

Plotting the graph, we get,

From the graph, we get,

AB = OB - OA = 5-3 = 2

AD = 2

BC = 6

Thus, quadrilateral ABCD is a trapezium, then,

Area of Quadrileral ABCD = ½ × (distance between parallel lines) = ½ × (AB) × (AD + BC)

= 8 sq units