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in Optics by (48.1k points)
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How does refractive index (μ) of a material vary with respect to wavelength (λ). (A and B are constants).

(a) μ = A + \(\frac{B}{λ^2}\) 

(b) μ = A + Bλ2

(c) μ = A +\(\frac{B}{λ}\) 

(d) μ = A + Bλ

1 Answer

+1 vote
by (48.5k points)
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Best answer

(a) μ = A + \(\frac{B}{λ^2}\) 

According to cauchy’s relation, (a) μ = A + \(\frac{B}{λ^2}\) 

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