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+1 vote
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in Optics by (48.2k points)
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Consider ffaunhoffer diffraction pattern obtained with a single slit illuminated at normal incident. At the angular position of the first diffraction minimum the phase difference between the wavelets from the opposite edges of the slits is

(a) \(\frac{π}{4}\) 

(b) \(\frac{π}{2}\) 

(c) 2π 

(d) π

1 Answer

+1 vote
by (48.6k points)
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Best answer

(c) 2π 

At the angular position of first minimum wavelets from opposite edges of the slits have a path difference of X and a phase difference of 2π radian.

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