Sarthaks Test
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Calculate the oxidation number of sulphur, chromium and nitrogen in H2SO5,  Cr2O72- and  NO3-

 Suggest structure of these compounds. Count for the fallacy. 

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(i)    H2+1SO3-2

However, the O.N. of S cannot be +8. S has six valence electrons. Therefore, the O.N. of S cannot be more than +6. 

The structure of H2SO5 is shown as follows: 

Therefore, the O.N. of S is +6. 

(ii)    Cr2O72-

Here, there is no fallacy about the O.N. of Cr in  Cr2O72-

The structure of   Cr2O72-

is shown as follows: 

Here, each of the two Cr atoms exhibits the O.N. of +6. 

(iii)    NO3-

Here, there is no fallacy about the O.N. of N in NO3-

The structure of  NO3-

is shown as follows: The N atom exhibits the O.N. of +5. 

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