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in Applications of Differential Calculus by (48.8k points)
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Find two positive numbers whose sum is 12 and their product is maximum.

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Best answer

Let the two numbers be x, 12 – x. 

Their product p = x (12 – x) = 12x – x2 

To find the maximum product. 

p'(x) = 12 – 2x 

p”(x) = -2 

p'(x) = 0 ⇒ 12 – 2x = 0 ⇒ 2x = 12 

⇒ x = 6 

at x = 6, p”(x) = -2 = -ve 

⇒ p is maximum at x = 6

when x = 6, 12 – x = 12 – 6 = 6 

So the two numbers are 6, 6

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