Let the length of the printed page be = x cm and breadth = y cm
Now xy = 24
⇒ y = 24/x ... (1)
The length of the paper = y + 3
Area A = (x + 2)(y + 3)
= xy + 3x + 2y + 6
= 24 + 3x + 2y + 6
= 3x + 2y + 30 … (2)
Substituting (1) in (2) we get
∴ Dimensions of the paper are
x + 2 = 4 + 2 = 6 cm
and y + 3 = 6 + 3 = 9 cm