Here,
a1 = √3
a2 = 2√3
a3 = 3√3
a4 = 4√3
a2 – a1 = 2√3 – √3 = √3
a3 – a2 = 3√3 – 2√3= √3
a4 – a3 = 4√3 – 3√3= √3
Since, difference of successive terms are equal,
Hence, √3 , 2√3, 3√3,… is an AP with common difference √3.
Therefore, the next three term will be,
4√3 + √3, 4√3 + 2√3, 4√3 + 3√3
5√3, 6√3, 7√3