Question

A proton and an a – particle are accelerated through the same potential difference. The ratio of de-Broglie wavelength of proton to the de-Broglie wavelength of alpha particle will be 

(a) 1 : 2 

(b) 2√2 :1 

(c) 2 : 1 

(d) 1:1

Answer 1

Correct answer is (b) 2√2 :1