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+1 vote
25.9k views
in Arithmetic Progression by (48.7k points)
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Show that the sum of an AP whose first term is a, the second term b and the last term c, is equal to \(\frac{(a+c)(b+c-2a)}{2(b-a)}\)

1 Answer

+2 votes
by (47.3k points)
selected by
 
Best answer

Given that, the AP is a, b, …, c.

Here, first term = a

common difference = b - a

and last term, an = c

as nth term of an AP

an = a + (n - 1)d

Sum of an AP

Hence Proved.

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