Question

If in two Δ PQR,AB/QR = BC/PR = CA/PQ, then

(a) Δ PQR~Δ CAB 

(b) Δ PQR ~ Δ ABC

(c) Δ CBA ~ Δ PQR 

(d) Δ BCA ~ Δ PQR

Answer 1

(a) Δ PQR ~ Δ CAB

Explanation:

From ∆ABC and ∆PQR, we have,

AB/QR = BC/PR = CA/PQ

If sides of one triangle are proportional to the side of the other triangle, and their corresponding angles are also equal, then both the triangles are similar by SSS similarity.

Therefore, we have,

Δ PQR~Δ CAB