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in Chemistry by (29.8k points)

Given the standard electrode potentials, 

K +/K = –2.93V, Ag+/Ag = 0.80V, Hg2+/Hg = 0.79V 

Mg2+/Mg = –2.37V. Cr3+/Cr = –0.74V 

Arrange these metals in their increasing order of reducing power. 

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1 Answer

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Answer: We have

The lower the electrode potential, the stronger is the reducing agent. Therefore, the increasing order of the reducing power of the given metals is Ag < Hg < Cr < Mg < K. 

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