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31.0k views
in Atomic and Nuclear Physics by (48.1k points)
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What is the distance of closest approach when a 5 MeV proton approaches a gold nucleus.

1 Answer

+1 vote
by (48.5k points)
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Best answer

q1 = ze 

q2 = e 

At the distance r0 of closest approach, 

K.E of a Proton = P.E. of proton and the gold nucleus

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