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To divide a line segment AB in the ratio 4:7, a ray AX is drawn first such that BAX is an acute angle and then points A1, A2, A3,…. are located at equal distances on the ray AX and the point B is joined to

(A) A12 (B) A11 (C) A10 (D) A9

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Best answer

(B) A11

According to the question,

A line segment AB in the ratio 4:7

So, A:B = 4:7

Now,

Draw a ray AX making an acute angle BAX

Minimum number of points located at equal distances on the ray,

AX = A+B = 4+7= 11

A1, A2, A3, ………. are located at equal distances on the ray AX.

Point B is joined to the last point is A11.

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