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To construct a triangle similar to a given ∆ABC with its sides 3/7 of the corresponding sides of ∆ABC, first draw a ray BX such that ∠CBX is an acute angle and X lies on the opposite side of A with respect to BC. Then, locate points B1,B2,B3,.......... on BX at equal distances and next step is to join

A. B10 to C

B. B3 to C

C. B7 to C

D. B4 to C

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C. B7 to C

Here, we locate points B1, B2, B3, B4, B5, B6 and B7 on BX at equal distance and in next step join the last points is B7 to C.

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