Question

The percentage of pyridine (C₅H₅N) that forms pyridinium ion (C₅H₅NH) in a 0.10M aqueous pyridine solution (Kb for C₅H₅N = 1.7 x 10^-9) is ……… 

(a) 0.006% 

(b) 0.013% 

(c) 0.77% 

(d) 1.6%

Answer 1

The percentage of pyridine (C₅H₅N) that forms pyridinium ion (C₅H₅NH) in a 0.10M aqueous pyridine solution (Kb for C₅H₅N = 1.7 x 10^-9) is 0.013% .

Percentage of dissociation 

=\(\sqrt{1.7}\) x 10^-4 x 100 

= 1.3 x 10^-2 

= 0.013%