Question

The solubility of AgCl (s) with solubility product 1.6 x 10^-10 in 0. 1 M NaCl solution would be ………

(a) 1.26 x 10^-5 M 

(b) 1.6 x 10^-9 M 

(c) 1.6 x 10^-11 M 

(d) Zero

Answer 1

(b) 1.6 x 10^-9 M 

AgCl (s) ⇌ Ag⁺ (aq) + Cl^- (aq)

K_sp = 1.6 x 10^-10

K_sp = [Ag⁺][Cl^-]

K = (s) (s + 0.1) 

0.1 >>s