Question

What is the angular momentum of an electron in the third orbit of an atom?

Answer 1

Here n = 3; h = 6.6 x 10^-34 Js

Angular momentum

L = \(\frac{nh}{2π}\) = \(\frac{3 \times 6.6 \times 10^{-34}}{2 \times 3.14}\) = 3.15 x 10^-34 Js