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in Nature of Physical World and Measurement by (48.5k points)
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In a submarine equipped with sonar, the time delay between the generation of a pulse and its echo after reflection from an enemy submarine is observed to be 80 sec. If the speed of sound in water is 1460 ms-1 . What is the distance of enemy submarine?

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Speed of sound in water = 1460 ms-1 

Time delay = 80s 

Distance of enemy ship = ? 

Solution:

Total distance covered = speed × time 

= 1460 ms-1 × 80s = 116800 m 

Time taken is for forward and backward path of sound waves.

Distance of enemy ship = \(\frac{total\,distance \,covered}{2}\) = \(\frac{116800}{2}\) m 

= 58400 m (or) 58.4 km

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