Question

The length of a rod as measured in an experiment was found to be 2.48 m, 2.46 m, 2.49 m, 2.50 m and 2.48 m. Find the average length, absolute error and percentage error. Express the result with error limit.

Answer 1

Average length = \(\frac{2.48 + 2.46 + 2.49 + 2.50 + 2.48}{5}\) = \(\frac{12.41}{5}\) = 2.48 m

Mean absolute error = \(\frac{0.00+0.052+0.01+0.02+0.00}{5}\) = \(\frac{0.05}{5}\) = 0.01 m

percentage error = \(\frac{0.01}{2.48}\) x 100% = 0.04 x 100% = 0.40%

Correct length = (2.48 ± 0.01) m

Correct length = (2.48 m ± 0.40%)