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in Trigonometry by (50.4k points)
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If f(x) = cos2x + sec2x, then

A. f(x) < 1
B. f(x) = 1
C. 2 < f(x) < 1
D. f(x) ≥ 2

[Hint: A.M ≥ G.M.]

1 Answer

+1 vote
by (49.0k points)
selected by
 
Best answer

D. f(x) ≥ 2

Explanation:

According to the question,

We have, f(x) = cos2x + sec2x

We know that, A.M ≥ G.M.

⇒ cos02x + sec2x ≥ 2

⇒ f(x) ≥ 2

Thus, option (D) f(x) ≥ 2 is the correct answer.

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