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Find principal argument of (1 + i√3)^2.

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Find principal argument of (1 + i√3)2.

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Best answer

Given z = (1 + i√3)2

= 1 – 3 + 2i√3

= -2 + i (2√3)

So, z lies in second quadrant.

= π – tan-1 √3

= π - π/3

= 2π/3

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