Question

A driver takes 0.20 second to apply the breaks (reaction time). If he is driving car at a speed of 54 kmh^-1 and the breaks cause a deceleration of 6.0 ms^-2 . Find the distance travelled by car after he sees the need to put the breaks.

Answer 1

(distance covered during 0.20 s) + (distance covered until rest)

= (15 x 0.25) + [18.75] = 21.75 m.