Question

A ball thrown vertically upwards with a speed of 19.6 ms^-1 from the top of a tower returns to the earth in 6s. Find the height of the tower, (g = 9.8 m/s)

Answer 1

s = ut + \(\frac{1}{2}\)at² 

-h = 19. 6 x 6 + x \(\frac{1}{2}\)(-9.8) x (6)² 

h = 58.8 m.