Question

Two bodies of masses 15 kg and 10 kg are connected with light string kept on a smooth surface. A horizontal force F = 500 N is applied to a 15 kg as shown in the figure. Calculate the tension acting in the string.

Answer 1

Given, 

m₁ = 15 kg, m₂ = 10 kg, F = 500 N 

Tension acting in the string T = \(\frac{m_2}{m_1 + m_2}\) F 

T = \(\frac{10}{25}\) x 500 = 200 N